你真的了解触发器么 数据实时同步更新问题剖析

我调整了触发器的代码，具体修改如下：

```sql

ALTER TRIGGER [dbo].[Table_a_Ins] ON [dbo].[Table_a] AFTER INSERT

BEGIN

DECLARE @ID INT

DECLARE cur_Insert CURSOR FOR SELECT ID FROM inserted

OPEN cur_Insert

FETCH NEXT FROM cur_Insert INTO @ID

WHILE @@FETCH_STATUS = 0

BEGIN

-- 更新Table_a表中的UpdateIDForTrigger字段，值为ID加10

UPDATE Table_a SET UpdateIDForTrigger = (@ID + 10)

WHERE ID = @ID

FETCH NEXT FROM cur_Insert INTO @ID

END

CLOSE cur_Insert

DEALLOCATE cur_Insert

END

```

```sql

INSERT INTO Table_a(Content) SELECT Content FROM Table_Info;

SELECT FROM Table_a;

```

运行后，没有错误提示，并且触发器的功能也得到了正确的执行。真是收获颇丰！在此基础上，结合前辈的建议，我对触发器的代码进行了进一步的优化。将原本使用的游标方式改为了更为简洁的优化方式。修改后的触发器代码如下：

```sql

ALTER TRIGGER [dbo].[Table_a_Ins] ON [dbo].[Table_a] AFTER INSERT

BEGIN

UPDATE Table_a

SET UpdateIDForTrigger = inserted.ID + 10

FROM inserted

WHERE Table_a.ID = inserted.ID;

END

```