Oracle 两个逗号分割的字符串,获取交集、差集(s

select regexp_substr(id, '[^,]+', 1, rownum) id
from (select '1,2,3,5' id from dual)
connect by rownum <= length(regexp_replace(id, '[^,]+')) +1
intersect -- 取交集
select regexp_substr(id, '[^,]+', 1, rownum) id
from (select '2' id from dual)
connect by rownum <= length(regexp_replace(id, '[^,]+')) +1;
/结果
2
/

select regexp_substr(id, '[^,]+', 1, rownum) id
from (select '1,2,3,5' id from dual)
connect by rownum <= length(regexp_replace(id, '[^,]+')) +1
minus --取差集
select regexp_substr(id, '[^,]+', 1, rownum) id
from (select '2' id from dual)
connect by rownum <= length(regexp_replace(id, '[^,]+')) +1;
/结果
1
3
5
/

function regexp_substr(strstr, pattern [,position] [,ourrence] [,modifier] [subexpression])
__srcstr需要进行正则处理的字符串
__pattern进行匹配的正则表达式
__position可选参数，表示起始位置，从第几个字符开始正则表达式匹配（默认为1）
__ourrence可选参数，标识第几个匹配组，默认为1
__modifier可选参数，表示模式（'i'不区分大小写进行检索；'c'区分大小写进行检索。默认为'c'。）

select 
regexp_substr('1,2,3,5','[^,]+') AS t1, 
regexp_substr('1,2,3,5','[^,]+',1,2) AS t2,
regexp_substr('1,2,3,5','[^,]+',1,3) AS t3,
regexp_substr('1,2,3,5','[^,]+',1,4) AS t4,
regexp_substr('1,2,3,5','[^,]+',2) AS t5,
regexp_substr('1,2,3,5','[^,]+',2,1) AS t6,
regexp_substr('1,2,3,5','[^,]+',2,2) AS t7
from dual; 

function regexp_substr(srcstr, pattern [,replacestr] [,position] [,ourrence] [,modifier])
__srcstr需要进行正则处理的字符串
__pattern进行匹配的正则表达式
__replacestr可选参数，替换的字符串，默认为空字符串
__position可选参数，表示起始位置，从第几个字符开始正则表达式匹配（默认为1）
__ourrence可选参数，标识第几个匹配组，默认为1
__modifier可选参数，表示模式（'i'不区分大小写进行检索；'c'区分大小写进行检索。默认为'c'。）

select 
regexp_replace('1,2,3,5','5','4') t1,
regexp_replace('1,2,3,5','2|3',4) t2,
regexp_replace('1,2,3,5','[^,]+') t3,
regexp_replace('1,2,3,5','[^,]+','') t4,
regexp_replace('1,2,3,5','[^,]+','') t5
from dual; 

select rownum from dual connect by rownum < 5;

select 
id,
name,
sys_connect_by_path(id,'\') idpath,
sys_connect_by_path(name, '\') namepath
from (
select 1 id, '广东' name, 0 pid from dual
union 
select 2 id, '广州' name , 1 pid from dual
union 
select 3 id, '深圳' name , 1 pid from dual
) 
start with pid = 0
connect by prior id = pid;

select regexp_substr(id, '[^,]+', 1, rownum) id
from (select '1,2,3,5' id from dual)
connect by rownum <= length(regexp_replace(id, '[^,]+')) +1