关于避免MySQL替换逻辑SQL的坑爹操作详解

create table helei1(
id int(10) unsigned NOT NULL AUTO_INCREMENT,
name varchar(20) NOT NULL DEFAULT '',
age tinyint(3) unsigned NOT NULL default 0,
PRIMARY KEY(id),
UNIQUE KEY uk_name (name)
)
ENGINE=innodb AUTO_INCREMENT=1 
DEFAULT CHARSET=utf8;

root@127.0.0.1 (helei)> select  from helei1;
+----+-----------+-----+
| id | name | age |
+----+-----------+-----+
| 1 | 贺磊 | 26 |
| 2 | 狼蚁网络推广 | 28 |
| 3 | 小红 | 26 |
+----+-----------+-----+
3 rows in set (0.00 sec)

root@127.0.0.1 (helei)> replace into helei1 (name) values('贺磊');
Query OK, 2 rows affected (0.00 sec)
root@127.0.0.1 (helei)> select  from helei1;
+----+-----------+-----+
| id | name | age |
+----+-----------+-----+
| 2 | 狼蚁网络推广 | 28 |
| 3 | 小红 | 26 |
| 4 | 贺磊 | 0 |
+----+-----------+-----+
3 rows in set (0.00 sec)
root@127.0.0.1 (helei)> replace into helei1 (name) values('爱璇');
Query OK, 1 row affected (0.00 sec)
root@127.0.0.1 (helei)> select  from helei1;
+----+-----------+-----+
| id | name | age |
+----+-----------+-----+
| 2 | 狼蚁网络推广 | 28 |
| 3 | 小红 | 26 |
| 4 | 贺磊 | 0 |
| 5 | 爱璇 | 0 |
+----+-----------+-----+
4 rows in set (0.00 sec)

root@127.0.0.1 (helei)> select  from helei1;
+----+-----------+-----+
| id | name | age |
+----+-----------+-----+
| 2 | 狼蚁网络推广 | 28 |
| 3 | 小红 | 26 |
| 4 | 贺磊 | 0 |
| 5 | 爱璇 | 0 |
+----+-----------+-----+
4 rows in set (0.00 sec)
root@127.0.0.1 (helei)> insert into helei1 (name,age) values('贺磊',0) on duplicate key update age=100;
Query OK, 2 rows affected (0.00 sec)
root@127.0.0.1 (helei)> select  from helei1;
+----+-----------+-----+
| id | name | age |
+----+-----------+-----+
| 2 | 狼蚁网络推广 | 28 |
| 3 | 小红 | 26 |
| 4 | 贺磊 | 100 |
| 5 | 爱璇 | 0 |
+----+-----------+-----+
4 rows in set (0.00 sec)
root@127.0.0.1 (helei)> select  from helei1;
+----+-----------+-----+
| id | name | age |
+----+-----------+-----+
| 2 | 狼蚁网络推广 | 28 |
| 3 | 小红 | 26 |
| 4 | 贺磊 | 100 |
| 5 | 爱璇 | 0 |
+----+-----------+-----+
4 rows in set (0.00 sec)
root@127.0.0.1 (helei)> insert into helei1 (name) values('爱璇') on duplicate key update age=120;
Query OK, 2 rows affected (0.01 sec)
root@127.0.0.1 (helei)> select  from helei1;
+----+-----------+-----+
| id | name | age |
+----+-----------+-----+
| 2 | 狼蚁网络推广 | 28 |
| 3 | 小红 | 26 |
| 4 | 贺磊 | 100 |
| 5 | 爱璇 | 120 |
+----+-----------+-----+
4 rows in set (0.00 sec)
root@127.0.0.1 (helei)> insert into helei1 (name) values('不存在') on duplicate key update age=80;
Query OK, 1 row affected (0.00 sec)
root@127.0.0.1 (helei)> select  from helei1;
+----+-----------+-----+
| id | name | age |
+----+-----------+-----+
| 2 | 狼蚁网络推广 | 28 |
| 3 | 小红 | 26 |
| 4 | 贺磊 | 100 |
| 5 | 爱璇 | 120 |
| 8 | 不存在 | 0 |
+----+-----------+-----+
5 rows in set (0.00 sec)