SQL Server 性能调优之查询从20秒至2秒的处理方法

select from(
 select ,ROW_NUMBER() OVER (ORDER BY sc desc) as rank 
 from(
  select ,
    case when ( 40-(a.p(case when a.p > 0 then 1 else -0.5 end)))<=30 
      then 30 
      else ( 40-(a.p(case when a.p > 0 then 1 else -0.5 end))) 
      end as sc 
  from (
  select  from (
    select a.ProjectNumber, a.ProjectName, a.BaojianNumber, a.BaojianName, a.ToubiaoPerson,
     sum(UnitPrice) as sumPrice, 
     b.price as avgPrice, 
     ((sum(UnitPrice)-b.price)/nullif(b.price,0)100) as p,
     sum(case when UnitPrice>b.price then b.price else UnitPrice end )as pprice,
     sum(case when UnitPrice>MaxPrice then 1 else 0 end ) as countChao
    from ToubiaoDetailTest1 a
      join (
       select ProjectNumber, ProjectName, BaojianNumber, BaojianName, avg(price) as price
       from(
        select  from(
         select ProjectNumber, ProjectName, BaojianNumber, BaojianName, ToubiaoPerson, 
          SUM(UnitPrice) as price,
          SUM(case when UnitPrice>MaxPrice then 1 else 0 end ) as countChao
         from ToubiaoDetailTest1 
         group BY ProjectNumber, ProjectName, BaojianNumber, BaojianName, ToubiaoPerson
        ) tt 
        where tt.countChao = 0
       ) t
       group by ProjectNumber, ProjectName, BaojianNumber, BaojianName
      ) b 
       on a.ProjectNumber=b.ProjectNumber and a.ProjectName=b.ProjectName and a.BaojianNumber=b.BaojianNumber and a.BaojianName=b.BaojianName
    group by a.BaojianNumber, a.BaojianName, a.ProjectNumber, a.ProjectName, a.ToubiaoPerson, b.price 
   ) tt 
   where tt.countChao=0
  ) a 
 ) b
) t 
order by rank