jQuery+php简单实现全选删除的方法

<input type="checkbox" id="ckb_selectAll" onclick="selectAll()" title="选中/取消选中">
<a href="javascript:void(0);" onclick="del_()" title="删除选定数据" style="font-weight:normal">删除</a>

<input type="checkbox" class="ckb" id="+con.id+" value="+con.id+">

function selectAll() {
  if ($('#ckb_selectAll').is(':checked')) {
    $(".ckb").attr("checked", true); //全部选中
  } else {
    $(".ckb").attr("checked", false);//全部取消
  }
}

function del_() {
  var ids = '';
  $(".ckb").each(function() {
    if ($(this).is(':checked')) {
      ids += ',' + $(this).val(); //逐个获取id
    }
  });
  ids = ids.substring(1); // 对id进行处理，去除第一个逗号
  if (ids.length == 0) {
    alert('请选择要删除的选项');
  } else {
    if (confirm("确定删除？删除后将无法恢复。")) {
      url = "action=del_call_record&ids=" + ids;
      $.ajax({
        type: "post",
        url: "send.php",
        data: url,
        suess: function(json) {
          if (parseInt(json.counts) > 0) {
            alert(json.des);
            location.reload();
          } else {
            alert(json.des);
          }
        },
        error: function(XMLHttpRequest, textStatus) {
          alert("页面请求错误，请检查重试或联系管理员！\n" + textStatus);
        }
      });
    }
  }
}

$ids = trim($_REQUEST['ids']);
$del_sql = "DELETE FROM vicidial_call_record WHERE id IN(".$ids.")";
//print_r($del_sql);exit;
if (mysqli_query($db_conn, $del_sql)) {
  $counts = "1";
  $des = "成功";
} else {
  $counts = "0";
  $des = "失败";
}
$json_data = "{";
$json_data. = "\"counts\":".json_encode($counts).",";
$json_data. = "\"des\":".json_encode($des)."";
$json_data. = "}";
echo $json_data;
break;