Laravel统一错误处理为JSON的方法介绍

<?php
/
  Author: sai
  Date: 2020/1/15
  Time: 14:31
 /

namespace App\Exceptions;


class ApiException extends \Exception
{
 const ERROR_CODE = 1001;
 const ERROR_MSG = 'ApiException';

 private $data = [];

 /
   BusinessException constructor.
  
   @param string $message
   @param string $code
   @param array $data
  /
 public function __construct(string $message, string $code, $data = [])
 {
  $this->code = $code ? : self::ERROR_CODE;
  $this->message = $message ? : self::ERROR_MSG;
  $this->data = $data;
 }

 /
   @return array
  /
 public function getData()
 {
  return $this->data;
 }

 /
   异常输出
  /
 public function render($request)
 {
  return response()->json([
   'data' => $this->getData(),
   'code' => $this->getCode(),
   'messgae' => $this->getMessage(),
  ], 200);
 }
}

<?php

namespace App\Exceptions;

use Exception;
use Illuminate\Foundation\Exceptions\Handler as ExceptionHandler;

class Handler extends ExceptionHandler
{
 /
   一些不需管或不需要抛出的异常
  /
 protected $dontReport = [
  ApiException::class,
 ];

 ...
}

<?php

namespace App\Http\Controllers;

use App\Exceptions\ApiException;
use Illuminate\Http\Request;

class HomeController extends Controller
{
 public function index(Request $request)
 {
  throw new ApiException('error', 10001, ['oh' => 'no']);
  return 1;
 }
}