JavaScript实现信用卡校验方法

网络编程 2021-07-04 21:47www.168986.cn编程入门
这篇文章主要介绍了JavaScript实现信用卡校验方法,涉及javascript使用Luhn算法进行校验的技巧,非常具有实用价值,需要的朋友可以参考下

本文实例讲述了JavaScript实现信用卡校验方法。分享给大家供大家参考。具体分析如下:

这里JavaScript版的信用卡校验代码,采用了Luhn算法

function isValidCreditCard(type, cum) {
  if (type == "Visa") {
   // Visa: length 16, prefix 4, dashes optional.
   var re = /^4\d{3}-?\d{4}-?\d{4}-?\d{4}$/;
  } else if (type == "MC") {
   // Mastercard: length 16, prefix 51-55, dashes optional.
   var re = /^5[1-5]\d{2}-?\d{4}-?\d{4}-?\d{4}$/;
  } else if (type == "Disc") {
   // Discover: length 16, prefix 6011, dashes optional.
   var re = /^6011-?\d{4}-?\d{4}-?\d{4}$/;
  } else if (type == "AmEx") {
   // American Express: length 15, prefix 34 or 37.
   var re = /^3[4,7]\d{13}$/;
  } else if (type == "Diners") {
   // Diners: length 14, prefix 30, 36, or 38.
   var re = /^3[0,6,8]\d{12}$/;
  }
  if (!re.test(cum)) return false;
  // Remove all dashes for the checksum 
  //checks to eliminate negative numbers
  cum = cum.split("-").join("");
  // Checksum ("Mod 10")
  // Add even digits in even length strings 
  //or odd digits in odd length strings.
  var checksum = 0;
  for (var i=(2-(cum.length % 2)); i<=cum.length; i+=2) {
   checksum += parseInt(cum.charAt(i-1));
  }
  // Analyze odd digits in even length strings
  //or even digits in odd length strings.
  for (var i=(cum.length % 2) + 1; i<cum.length; i+=2) {
   var digit = parseInt(cum.charAt(i-1)) * 2;
   if (digit < 10) { checksum += digit; }
   else { checksum += (digit-9); }
  }
  if ((checksum % 10) == 0) return true; else return false;
}

希望本文所述对大家的javascript程序设计有所帮助。

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