AngularJS中如何使用$parse或$eval在运行时对Scope变量

<table-helper datasource="customers" clumnmap="[{name: 'Name'}, {street: 'Street'}, {age: 'Age'}, {url: 'URL', hidden: true}]"></table-helper>

return {
restrict: 'E',
scope: {
columnmap: '=',
datasource: '='
},
link:link,
template:template
}; 

<table-helper-with-parse datasource="customers" columnmap="[{name: 'Name'},...]"></table-helper-with-parse>

var tableHelperWithParse = function($parse){
var template = "",
link = function(scope, element, attrs){
var headerCols = [],
tableStart = '<table>',
tableEnd = '</table>',
table = '',
visibleProps = [],
sortCol = null,
sortDir = 1,
columnmap = null;
$scope.$watchCollection('datasource', render);
//运行时赋值columnmap
columnmap = scope.$eval(attrs.columnmap);
//或者
columnmap = $parse(attrs.columnmap)();
wireEvents();
function rener(){
if(scope.datasource && scope.datasourse.length){
table += tableStart;
table += renderHeader();
table += renderRows() + tableEnd;
renderTable();
}
}
};
return {
restrict: 'E',
scope: {
datasource: '='
},
link: link,
template: template
}
}
angular.module('direcitvesModule')
.directive('tableHelperWithParse', tableHelperWithParse);

var getter = $parse('user.name'); 
var setter = getter.assign; 
setter(scope, 'new name');
getter(context, locals) // 传入作用域，返回值
setter(scope,'new name') // 修改映射在scope上的属性的值为‘new value'

$eval: function(expr, locals) {
return $parse(expr)(this, locals);
},