Jquery ajax加载等待执行结束再继续执行下面代码操

$(document).ready(function(){ 
  loadphpernote(); 
  window.open('http://.phpernote.'); 
}); 
function loadphpernote(){ 
  var url='http://.phpernote./ajax.php'; 
  var data='action=list'; 
  jQuery.ajax({ 
    type:'post', 
    url:url, 
    data:para, 
    async:false,//false代表只有在等待ajax执行完毕后才执行window.open('http://.phpernote.')语句 
    suess:function (msg){ 
      $('#articleList').html(msg); 
    } 
  }); 
} 

 var dates = this.options.form.getWidgetByName("dates").getValue(); 
 $.ajax({  
  url: "http://127.0.0.1:9009/Brilliantzz/service/snproduct.do",  
  data:dates, 
beforeSend:function() { 
   var h = document.body.clientHeight;  
 $("<div class=\"datagrid-mask\"></div>").css({display:"block",width:"100%",height:h}).appendTo("body");  
 $("<div class=\"datagrid-mask-msg\"></div>").html("正在上传生产数据，请稍候。。。").appendTo("body").css({display:"block", 
 left:($(document.body).outerWidth(true) - 190) / 2, 
 :(h - 45) / 2}); 
  }, 
plete:function(data) { 
     $('.datagrid-mask-msg').remove(); 
  $('.datagrid-mask').remove(); 
  }, 
  suess: function(data) { 
    alert("生产数据:"+data);   
  }, 
  error: function(data) { 
       alert("上传生产数据异常！"); 
      } 
    });