p5.js 毕达哥拉斯树的实现代码

function Pythagorian(x){
 noStroke();
 fill(107, 142, 35,map(x, 0, a, 150, 255));//根据正方形边长设置填充色
 rect(0,0,x,x);//绘制当前的正方形
 
 if(x <= 3) return 0;//当正方形边长小于3时，结束递归

 / 绘制右上角的正方形 / 
 push();
 rotate(PI / 2 - t);//坐标轴顺时针旋转约37deg
 translate(0,-x/5  3 - x/54);//坐标轴向上平移3边+4边的长度
 Pythagorian(x/54);//递归调用毕达哥拉斯函数
 pop();
 
 / 绘制左上角的正方形 /
 push();
 rotate( - t);//坐标轴逆时针旋转约53deg
 translate(0,-x/5  3);//坐标轴向上平移3边的长度
 Pythagorian(x/53);//递归调用毕达哥拉斯函数
 pop(); 
 
}

var a = 100; //最大正方形边长
var t;//4边所对应的角度
function setup(){
 t = 53.1301024 / 360  2  PI;//约为53deg
 createCanvas(windowWidth, windowHeight);//创建画布
 background(255);
 noLoop();//draw()函数只执行一次
}

function draw(){
 translate(windowWidth/2, windowHeight - a  2);//将坐标系平移至画布中间底部
 Pythagorian(a);//调用毕达哥拉斯递归函数
}

var a = 100;
var t;
function setup(){
 t = 53.1301024 / 360  2  PI;
 createCanvas(windowWidth, windowHeight);
 background(255);
 noLoop();
}
function draw(){
 translate(windowWidth/2, windowHeight - a  2);
 Pythagorian(a);
 
}
function Pythagorian(x){
 noStroke();
 fill(107, 142, 35,map(x, 0, a, 150, 255));
 rect(0,0,x,x);
 
 if(x <= 3) return 0;
 
 push();
 rotate(PI / 2 - t);
 translate(0,-x/5  3 - x/54);
 Pythagorian(x/54);
 pop();
 
 push();
 rotate( - t);
 translate(0,-x/5  3);
 Pythagorian(x/53);
 pop(); 
 
}