JS实现深度优先搜索求解两点间最短路径

const map = [
  [0, 1, 1, 0, 1],
  [1, 0, 0, 1, 0],
  [1, 0, 0, 0, 1],
  [0, 1, 0, 0, 0],
  [1, 0, 1, 0, 0]
]

function dfsManager(map, start, end){

  var min = 9999,
    path = [],
    unvisited = [];
  for(let i=0; i<5;i++){
    unvisited[i] = true
  }

  (function dfs(map, start, end, step){
    //unvisited[start] = false //不重复访问的节点
    if(start === end){
      console.log('step:',step)
      for(let i=0; i<path.length; i++){
        if(path[i] >= 0){
          console.log(path[i]+'->')
        }
      }
      if(min > step){
        min = step
      }
      return
    }
    unvisited[start] = false  //要重复访问的节点
    let len = map.length

    for(let i=0; i<len; i++){
      if(map[start][i] === 1 && unvisited[i]){
        path.push(i)  //记录路径
        dfs(map, i, end, step+1)
        path.pop()   //避免污染其他路径
      }
    }
  })(map, start, end, 0)

  return min
}

console.log('min:',dfsManager(map,3,4))