jquery 插件重新绑定的处理方法分析

<div class="expert">
  <div class="expert-list">
    <ul>
      <li class="expert-item">
        <a href="#" rel="external nofollow" rel="external nofollow" >
          <img src="./imgs/expert1.jpg" />
        </a>
      </li>
      <li class="expert-item">
        <a href="#" rel="external nofollow" rel="external nofollow" >
          <img src="./imgs/expert2.jpg" />
        </a>
      </li>
    </ul>
    <a class="prev" href="javascript:void(0)" rel="external nofollow" rel="external nofollow" ></a>
    <a class="next" href="javascript:void(0)" rel="external nofollow" rel="external nofollow" ></a>
  </div>
</div>

<script type="text/javascript">
  $(".expert-list").slide({mainCell: "ul", autoPage: true, effect: "left", autoPlay: true});
</script>

<script type="text/javascript">
  var expert = $(".expert").clone();
  $(".expert-list").slide({mainCell: "ul", autoPage: true, effect: "left", autoPlay: true});
  $(window).resize(function () {
    $(".expert").empty();
    //这里只需添加html结构，clone()好像会把行内样式也拷贝了。
    $(".expert").append(expert.html());
    $(".expert-list").slide({mainCell: "ul", autoPage: true, effect: "left", autoPlay: true});
  });
</script>