详解css-vars-ponyfill 在ie环境下使用问题（nextjs 构

export function browser() {
  const UA = window.navigator.userAgent
  if (UA.includes("qqbrowser")) return "qqbrowser"
  if (UA.includes("baidu")) return "baidu"
  if (UA.includes("Opera")) return "Opera"
  if (UA.includes("Edge")) return "Edge"
  if (UA.includes("MSIE") || (UA.includes("Trident") && UA.includes("rv:11.0")))
    return "IE"
  if (UA.includes("Firefox")) return "Firefox"
  if (UA.includes("Chrome")) return "Chrome"
  if (UA.includes("Safari")) return "Safari"
}

type CommonLinkProps = {
    children: ReactElement
    href?: string
    target?: string
    outerLink?: boolean
    styles?: unknown
}
export default function CustomLink(props: CommonLinkProps) {
  const { children, href, target, as, outerLink, styles = emptyStyles } = props
  const [isIE, setIE] = useState<boolean>(false)
  const cloneEl = (c: ReactElement, props?: any) =>
    React.cloneElement(c, { href: as ?? href, target, ...props })
  useEffect(() => {
    if (["IE", "qqbrowser", "baidu"].includes(browser())) {
      setIE(true)
    }
  }, [])
  function renderLink() {
    if (Children.only(children).type === "a") {
      const node = cloneEl(children as ReactElement)
      return node
    } else {
      let fn: () => void | null = null
      if (outerLink) {
        fn = () => {
          window.open(as ?? href)
        }
      } else {
        fn = () => {
          window.location.href = as ?? href
        }
      }
      const node = cloneEl(children as ReactElement, {
        onClick: () => {
          fn()
        },
      })
      return node
    }
  }

  return (
    <>
      {!href ? (
        children
      ) : isIE ? (
        renderLink()
      ) : (
        <Link {...props}>{children}</Link>
      )}
      <style jsx>{styles}</style>
    </>
  )
}